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Ultimate Guide to Complex Geometry (Part 1): The Argand Diagram and Polar Form

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    Vu Hung
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Introduction

So far, we have treated complex numbers purely algebraically, adding and multiplying them like algebraic expressions. But complex numbers possess a profound geometric interpretation. In Complex Geometry (Part 1), we move from the 1D number line to the 2D complex plane (the Argand diagram). By thinking of complex numbers as points or vectors in a 2D space, you will unlock a much more intuitive way to understand their behavior, leading to the powerful Modulus-Argument (Polar) form.

Executive Summary

This guide introduces the geometric foundations of the complex plane:

  • The Complex Plane (Argand Diagram): Plotting z=x+iyz = x + iy as coordinates (x,y)(x, y).
  • The Argument (argz\arg z): Defining the angle a complex number makes with the positive real axis.
  • The Principal Argument (Arg z\text{Arg } z): Restricting the angle to the unique interval (π,π](-\pi, \pi].
  • Modulus-Argument (Polar) Form: Writing complex numbers as z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta).

What is this about?

Real numbers live on a 1D line. You can only move left (negative) or right (positive). But because a complex number z=x+iyz = x + iy has two independent components (a real part xx and an imaginary part yy), it cannot fit on a single line.

Instead, it requires a 2D grid. The horizontal axis represents the real part, and the vertical axis represents the imaginary part. Once plotted on this grid (the Argand diagram), we can describe a complex number's position in two ways:

  1. Cartesian coordinates: How far left/right and how far up/down it is (x,yx, y).
  2. Polar coordinates: How far away it is from the origin (rr) and what direction it is pointing (θ\theta).

Converting between these two forms is an essential skill for the HSC exam.

Main Content

1. The Complex Plane (Argand Diagram)

To graph a complex number z=x+iyz = x + iy, we use a standard Cartesian plane, but we rename the axes:

  • The x-axis becomes the Real Axis (Re\text{Re}).
  • The y-axis becomes the Imaginary Axis (Im\text{Im}).

The complex number z=x+iyz = x + iy is plotted as the point (x,y)(x, y). For example:

  • z1=3+4iz_1 = 3 + 4i is plotted at (3,4)(3, 4) in the first quadrant.
  • z2=2+iz_2 = -2 + i is plotted at (2,1)(-2, 1) in the second quadrant.
  • z3=5z_3 = -5 is plotted at (5,0)(-5, 0) directly on the negative Real Axis.
  • z4=2iz_4 = -2i is plotted at (0,2)(0, -2) directly on the negative Imaginary Axis.

2. The Argument of a Complex Number

If you draw a line from the origin (0,0)(0,0) to the point z=x+iyz = x + iy, that line creates an angle with the positive Real Axis. This angle is called the argument of zz, denoted as arg(z)\arg(z) or θ\theta.

Using basic right-angled trigonometry: tanθ=yx\tan\theta = \frac{y}{x}

Because you can rotate around the origin 360360^\circ (or 2π2\pi radians) and end up pointing in the exact same direction, a complex number has infinitely many valid arguments. They all differ by multiples of 2π2\pi.

3. The Principal Argument (Arg z\text{Arg } z)

To avoid confusion with infinite answers, mathematicians defined the principal argument, denoted with a capital 'A': Arg(z)\text{Arg}(z).

The principal argument is the unique angle chosen from the interval: π<Arg(z)π-\pi < \text{Arg}(z) \le \pi

How to calculate the Principal Argument:

  1. Draw a quick sketch to determine which quadrant the point is in.
  2. Calculate the base acute angle α=tan1yx\alpha = \tan^{-1}\left|\frac{y}{x}\right|.
  3. Adjust based on the quadrant:
    • Quadrant 1 (x>0,y>0x>0, y>0): Arg(z)=α\text{Arg}(z) = \alpha
    • Quadrant 2 (x<0,y>0x<0, y>0): Arg(z)=πα\text{Arg}(z) = \pi - \alpha
    • Quadrant 3 (x<0,y<0x<0, y<0): Arg(z)=(πα)\text{Arg}(z) = -(\pi - \alpha)
    • Quadrant 4 (x>0,y<0x>0, y<0): Arg(z)=α\text{Arg}(z) = -\alpha

Note: The argument of 00 is undefined, because the point (0,0)(0,0) has no direction.

4. Modulus-Argument (Polar) Form

We know the distance from the origin is the modulus r=z=x2+y2r = |z| = \sqrt{x^2+y^2}, and the angle is θ=arg(z)\theta = \arg(z). Using trigonometry, we can express the Cartesian coordinates (x,y)(x, y) in terms of rr and θ\theta: x=rcosθx = r\cos\theta y=rsinθy = r\sin\theta

Substitute these into z=x+iyz = x + iy: z=rcosθ+i(rsinθ)z = r\cos\theta + i(r\sin\theta) z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta)

This is the Modulus-Argument or Polar form of a complex number. In many Australian textbooks, this is abbreviated using the "cis" notation: z=r cis θz = r \text{ cis } \theta (where "cis" stands for cos + i sin).

Simple Worked Example

Question: Convert z=13iz = -1 - \sqrt{3}i into modulus-argument (polar) form.

Solution: Step 1: Find the modulus (rr) r=z=x2+y2r = |z| = \sqrt{x^2 + y^2} r=(1)2+(3)2r = \sqrt{(-1)^2 + (-\sqrt{3})^2} r=1+3=4=2r = \sqrt{1 + 3} = \sqrt{4} = 2

Step 2: Find the principal argument (θ\theta) The point is (1,3)(-1, -\sqrt{3}), which is in the Third Quadrant. Find the acute base angle α\alpha: α=tan131=tan1(3)\alpha = \tan^{-1}\left|\frac{-\sqrt{3}}{-1}\right| = \tan^{-1}(\sqrt{3}) From exact values, α=π3\alpha = \frac{\pi}{3}. Because we are in the third quadrant, the principal argument is: θ=(πα)=(ππ3)=2π3\theta = -(\pi - \alpha) = -(\pi - \frac{\pi}{3}) = -\frac{2\pi}{3}

Step 3: Write in polar form z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta) z=2(cos(2π3)+isin(2π3))z = 2\left(\cos\left(-\frac{2\pi}{3}\right) + i\sin\left(-\frac{2\pi}{3}\right)\right) Or, using abbreviation: z=2 cis (2π3)z = 2 \text{ cis }\left(-\frac{2\pi}{3}\right)

mini-FAQ page

Q: Do I have to use radians? Can I use degrees? A: In HSC Extension 2, you must always use radians for complex number arguments unless a specific question explicitly asks for degrees. Using degrees can lose you marks, especially when we start looking at complex number geometry and regions later on.

Q: Is 4π3\frac{4\pi}{3} a valid argument for 13i-1-\sqrt{3}i? A: It is a valid argument (lowercase arg(z)\arg(z)), but it is NOT the principal argument (uppercase Arg(z)\text{Arg}(z)). Because 4π3\frac{4\pi}{3} is greater than π\pi, it falls outside the restricted range (π,π](-\pi, \pi]. You must subtract 2π2\pi to get the principal argument: 4π32π=2π3\frac{4\pi}{3} - 2\pi = -\frac{2\pi}{3}.

Common mistakes to avoid

  • Blindly typing tan1(y/x)\tan^{-1}(y/x) into the calculator: If you type tan1(1/1)\tan^{-1}(-1/-1), the calculator gives π4\frac{\pi}{4} (Quadrant 1). But 1i-1-i is in Quadrant 3! The calculator cannot tell the difference between 11\frac{-1}{-1} and 11\frac{1}{1}. Always draw a sketch to identify the correct quadrant before calculating the angle.
  • Forgetting the brackets: Writing 2cosπ3+isinπ32 \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} is mathematically incorrect because the 22 only multiplies the cosine term. You must write 2(cosπ3+isinπ3)2\left(\cos\frac{\pi}{3} + i\sin\frac{\pi}{3}\right).

Practice on Vu's Maths Hub

Converting fluidly between Cartesian and polar form is a non-negotiable skill for Extension 2.

Further Readings

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